In order to solve problems which require application of the

area and

perimeter for trapezoids, it is necessary to

In a typical problem involving

area and

perimeter of a trapezoid, we are given some measurements of the bases, height, area, or

perimeter and asked to calculate the others. The problem can be easier if we know that the

trapezoid is isosceles (the non-parallel sides are of equal length).

Two diagrams that illustrate these given are shown below. Notice that s

_{1}> s

_{2} and that

symmetry is not a condition of the trapezoid. Unfortunately, we could construct infinitely many trapezoids with bases of 8 and 5 and a

height of 4.

Although we can NOT find the

perimeter because the possible trapezoids which we can draw can have different lengths for the other two sides, we can, interestingly enough, find the

area of any

trapezoid meeting the

base and

height requirements by using the formula

A = (½ h)(B + b)

A = (2)(13)

A = 26

Notice the importance of making a diagram (or more than one) to see what is happening when using the given information.