Introduction: In this lesson, three trigonometric identities will be derived and applied. These involve squares of the basic trig functions and are know as the Pythagorean Identities.
The Lesson: In a right triangle, one angle is and the side across from this angle is called the hypotenuse. The two sides which form the 90º angle are called the legs of the right triangle. We show a right triangle below. The legs are defined as either “opposite” or “adjacent” (next to) the angle A. 
We shall abbreviate opposite as “opp,” adjacent as “adj,” and hypotenuse as “hyp.”
Using the Pythagorean Theorem we have 
Dividing both sides of this equation by
and using the relationships sin(A) =
and cos(A) =
results in 
Continuing, if we divide both sides of
by
we have 
which simplifies to
.
Finally, if we divide both sides of
by
we have 
which simplifies to 
Summary: The three Pythagorean Identities are: 


These can be rewritten by subtracting from both sides: 


Identities: It is not as easy to find angle and side measurements of triangles using the reciprocal functions as it is to use sine, cosine, and tangent. This is primarily because the calculators typically have sin, cos, and tan keys and not keys for the reciprocal functions. However, we can use these reciprocal functions to provide identities which are equations relating trig functions to each other.
An example of an identity with the variable x is 2x(3 – x) = 6x – 2x2.
This statement is true for ALL values of x.
An identity involving trig functions is
. This statement is true for any angle A.
A second example of a trig identity is tan(A)csc(A) = sec(A).
To show that this statement is true, substitute
and simplify.
tan(A)csc(A) =
.
Let's Practice: - In a triangle ABC, with B a right angle, suppose the sin(A) = 0.25. What is the cos(A)?
We know that
.
Therefore
.
This gives us cos(A) =
.
In this case we took the positive square root since trig function values are positive for angles less than 90º.
- In a triangle XYZ with Y a right angle, suppose the tan(X) = 3. What is cot(X)? What is sec(X)?
We know that cot(X) =
.
We did not need a Pythagorean Identity for this.
We also know that 
Therefore
.
- If sin(A) = 0.3 and angle A is a second quadrant angle, what is cos(A)? What is tan(A)?
We know that
.
Therefore
.
This gives cos(A) =
.
We take the negative square root since cosine is negative for a second quadrant angle. To assist you with making these decisions on signs, refer to this lesson on reference angles.
To find the tan(A) we use tan(A) = 
- Simplify (1 – sin(A))(1 + sin(A)).
We use the fact that
to multiply (1 – sin(A))(1 + sin(A)).
The result is
.
Therefore (1 – sin(A))(1 + sin(A)) = cos2(A).
- Show that
.
We start by getting a common denominator for the fractions:
.
Then we can write
.